Answer:
Q = 4180 J
Explanation:
Given data:
Mass of water = 10.0 g
Initial temperature = 0°C
Final temperature = 100°C
Heat required = ?
Solution:
Specific heat capacity of water is 4.18 j/g.°C.
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = 100°C - 0°C
ΔT = 100°C
Q = 10.0 g ×4.18 j/g.°C × 100°C
Q = 4180 J
