Answer:
[tex]x \leq 5[/tex]
Step-by-step explanation:
[tex]3(2x-1)\leq 4x+7[/tex]
First, we have to distribute the 3 in the parentheses. That gets to: [tex]6x-3\leq 4x+7[/tex]
Now we have to subtract 4x and add 3 on both sides. That gets to: [tex]2x\leq10[/tex]
Now we have to divide 2 on both sides. That gets to [tex]x \leq 5[/tex].
Hope this helped! If not, please let me know!
