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265. The perimeter of a rectangle
is 58 meters. The width of the
rectangle is five meters less than
the length. Find the length and the
width of the rectangle.

Respuesta :

Answer:

L = 17 m, W = 12 m

Explanation:

W = (L - 5) m

 

P = 2(L + W) = 58 m

 

Substitute W = L - 5 from the first equation into the second equation and get L:

 

2[L + (L - 5)] = 58

 

2(2L - 5) = 58

 

2L - 5 = 58/2 = 29

 

L = (29 + 5)/2 = 17

 

Then W = L - 5 = 17 - 5 = 12

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