Answer:
When 16.1 g of octane burn 1.12 moles of CO₂ are emitted in atmosphere.
Explanation:
Given data:
Mass of octane C₈H₁₈ = 16.1 g
Moles of CO₂ emitted = ?
Solution:
Chemical equation:
2C₈H₁₈ + 25O₂ → 16CO₂+ 18H₂O
Number of moles of octane:
Number of moles = mass/molar mass
Number of moles = 16.1 g/ 114.23 g/mol
Number of moles = 0.14 mol
Now we will compare the moles of octane with carbon dioxide.
C₈H₁₈ : CO₂
2 : 16
0.14 : 16/2×0.14 = 1.12 moles
When 16.1 g of octane burn 1.12 moles of CO₂ are emitted in atmosphere.
