Answer:
[tex]\huge\boxed{(f-g)(x)=3x^2+6}[/tex]
Step-by-step explanation:
[tex](f-g)(x)=f(x)(x)\\\\\text{substitute}\ f(x)=4x^2+1\ \text{and}\ g(x)=x^2-5\\\\(f-g)(x)=(4x^2+1)-(x^2-5)=4x^2+1-x^2-(-5)=4x^2+1-x^2+5\\\\\text{combine like terms}\\\\(f-g)(x)=(4x^2-x^2)+(1+5)=3x^2+6[/tex]
