Answer:
14.4m
Explanation:
u = 0 i.e it started from rest
acceleration (a) = 3.2m/s2
time taken (t) = 3.0s
Using the second equation of motion:
s = ut + 1/2at2
s = 0(3.0) + 1/2(3.2)(3.0)2
s = 1.6(9.0)
s = 14.4m
hence the distance covered within that time is 14.4m.