The answer is "0.22 feet below the marker".
Given equation:
[tex]y = 3 \cos (\frac{24 \pi}{ 149}x)\\\\[/tex]
To find:
height of water at 2:15 am=?
Solution:
[tex]y = 3 \cos (\frac{24 \pi}{ 149}x)\\\\[/tex]
where x is the time in hours that is 11:00 p.m and at the of time 2:15 am the calculating value of x:
[tex]\to X= (3:15)\ hours = 3 \frac{1}{4} = \frac{13}{4}\\\\ \to y= 3 \cos (\frac{24 \pi}{149}\times \frac{13}{4} )\\\\[/tex]
[tex]= 3 \cos (\frac{6 \pi}{149}\times 13 )\\\\= 3 \cos (\frac{78\pi}{149} )\\\\= -0.22118\approx -0.22\\\\[/tex]
Therefore, the height of the water at 2:15 am is 0.22 feet below the marker.
Learn more:
brainly.com/question/1970024
