Respuesta :

tqiu

Answer:

1/2020

Step-by-step explanation:

We can set up an equation, where x is the number that, when divided by itself, is 2020 times itself:

x/x = 2020*x

The left-hand side reduces to 1:

1 = 2020*x

Now, you can divide both sides by 2020:

x = 1/2020

To check, we can divide 1/2020 by itself:

[tex]\frac{\frac{1}{2020}} {\frac{1}{2020}} = \frac{1}{2020}\cdot \frac{2020}{1} = \frac{2020}{2020} = 1[/tex]

1 is indeed 2020 times 1/2020.

okpalawalter8

We have that

x=4.95*10^{-4}

From the question we are told

What is the only real number which, when divided by itself, is 2020

times itself

Generally the equation for the statement  is mathematically given as

[tex]\frac{x}{x}=2020*x\\\\1=2020*x\\\\x=\frac{1}{2020}\\\\x=4.95*10^{-4}[/tex]

Hence

the only real number which, when divided by itself, is 2020

times itself is

[tex]x=4.95*10^{-4}[/tex]

For more information on this visit

https://brainly.com/question/23366835

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