Answer:
f(x) = (x^2-16) / (x+3)
f(x) has no horizontal asymptote.
Vertical assymptote is x = -3
Dividing the numerator by the denominator gives x - 3 remainder -7. Therefore, the oblique assymptote is x - 3.
the vertical asymptotes of the function f(x) = (5x + 1) / (x^2 + x - 6) = (5x + 1)/(x - 2)(x + 3) is x = 2 and x = -3.
the zeros of the function f(x) = (3x^2 - 3x - 6 ) / (3x - 6) = (3x^2 + 3x - 6x - 6) / (3x - 6) = (3x(x + 1) - 6(x + 1)) / (3x - 6) = (3x - 6)(x + 1)/(3x - 6) = x + 1 is x = -1
the function f(x) = (x^2 + x - 12) / (x - 3) = (x - 3)(x + 4) / (x - 3) is --> disc = 3, x-int = (-4, 0), y-int = 4? basic shape = straight line
Step-by-step explanation:
Hope this helps! brainliest please
