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In trapezoid EFGH , EF¯¯¯¯¯ and HG¯¯¯¯¯¯ are the bases. Point J is the midpoint of EH¯¯¯¯¯¯ and point K is the midpoint of FG¯¯¯¯¯ . EF=3x+2 , HG=7x−2 , and JK=25 .

What is the value of x?

Respuesta :

Answer:

Step-by-step explanation:

EF - base1

HG - base2

J-midpoint of EH

K-midpoint of FG

We are solving it by using formula:

JK=(base1+base2):2

25=(3x+2+7x-2):2

25*2=10x

50=10x

x=50:10

x=5

Good luck!

Answer:

X=5

Step-by-step explanation:

The two bases added together divided by two should equal the mid segment which is 25. Plugging in the equation. You have (3x + 2) + (7x - 2) divided by 2. 7x + 3x = 10x. Then 2-2 cancel each other out. 10x/2 = 5x. 5x = 25. When you simplify it you get x = 5.