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The soccer team is conducting a fundraiser selling long-sleeved T-shirts for $14 and short-sleeved T-shirts for $10. So far the team has sold less than $200 worth of the two types of T-shirts. Which inequality best represents x, the number of long-sleeved T-shirts they have sold, and y, the number of short-sleeved T-shirts they have sold?

x + y 200
14x + 10y > 200
14x + 10y < 200

Respuesta :

Answer:

14x +10y < 200

Step-by-step explanation:

The inequality that represents the given condition is: 14x + 10 y < 200.

What is an inequality?

"An inequality is a relation which makes a non-equal comparison between two numbers or other mathematical expressions."

Given, the price per long sleeved t-shirt is $14.

The price per short sleeved t-shirt is $10.

The soccer team has sold less than $200 worth of both types of t-shirts.

Here, the number of long-sleeved t-shirts they have sold is 'x'.

The number of short-sleeved t-shirts they have sold is 'y'.

Therefore, the total price of long sleeved t-shirt sold is = $14 × x = $14x

The total price of short sleeved t-shirt sold is = $10 × y = $10y

Therefore, the required inequality will be:

14x + 10 y < 200

Learn more about an inequality here: https://brainly.com/question/18342668

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