What is the depth of the crater if the time is 6.3 s? An astronaut stands by the rim of a crater on the moon, where the acceleration of gravity is 1.62 m/s2. To determine the depth of the crater, she drops a rock and measures the time it takes for it to HIT the bottom

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Complete Question

An astronaut stands by the rim of a crater on the moon, where the acceleration of gravity is 1.62 m/s2. To determine the depth of the crater, she drops a rock and measures the time it takes for it

to hit the bottom. If the time is 6.3 s, what is the depth of the crater?

Answer:

The depth is 32 m

Explanation:

From the question we are told that

  The  time is  t =  6.3 s

  The acceleration due to gravity is  [tex]g =  1.62 \  m/s^2[/tex]

 

Generally from kinematic equation

    [tex]s = ut + \frac{1}{2}  - at^2[/tex]

Here the u is the initial  velocity and the value is  0 m/s

      [tex]s = 0 + \frac{1}{2}  - (1.62) * (6.3)^2[/tex]

        [tex]s = 32 \ m [/tex]