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A certain pipe can fill up a tank 2 hours faster than another pipe. It takes 3 and hours for both pipes to fill up the same tank. In how many hours would the first pipe fill up the tank?​

Respuesta :

samuelonum1

Answer:

1 hour

Step-by-step explanation:

let the pipe take x hours to fill a house

then the second pipe will take=(x+2) hours

the combined time to fill up the house is 3 hours

so

1/(x+2)+1/2=1/3-----this is the combined work rate for both pipes

the lcm is 2(x+2)

(2+x+2)/2(x+2)=1/3

x+4/2(x+2)=3

cross multiply we have

x+4=3(x+2)

x+4=3x+6

3x+6-x-4=0

3x-x+6-4=0

2x+2=0

2x=-2

x=-1

The time is 1 hour

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