Answer:
[tex]7 \leq x \leq 9[/tex]
Step-by-step explanation:
Let [tex]x[/tex] represent the real numbers.
For the first part, all real numbers less than or equal to 9 in algebra is [tex]x \leq 9[/tex].
For the second part, all real numbers greater than or equal to 7 in algebra is [tex]x \geq 7[/tex].
To combine both inequalities, it would become [tex]7 \leq x \leq 9[/tex].
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The real numbers are 7, 8, and 9.
We are given two statements:
We have to use these two statements, form an inequality for the real number and find the real numbers.
Inequality is a relation that makes a non-equal comparison between two mathematical expressions.
There are five types of inequality:
[tex]Less~~than~ = ~ < \\Greater~~than~=~ > \\Less~~than~~or~~equal~~to~=~\le\\Greater~~than~~or~~equal~~to~=~\ge[/tex]
Let the real number be x.
Now using the two given statements we have,
[tex]x\le9\\x\ge7[/tex]
If we combine these two equations we get,
[tex]7\le x \le 9[/tex]
Thus we can say that the real numbers are 7, 8, and 9.
Learn more about inequalities of real numbers here:
https://brainly.com/question/27997176
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