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A speeding Thunderbird left skid marks on the road that were 76.7 m long when it came to a stop. If the acceleration of the car was -10 m/s2, how fast was the car initially going?

Respuesta :

GeorgePP

Answer: 39.2 m/s

Explanation:

You can use the kinematic equation:

[tex]v_f^2=v_i^2+2a*d[/tex]

We know the final velocity because it says it came to a stop. So now all we gotta do is plug in.

[tex]0^2=v_i^2+2(-10)(76.7)\\v_i^2=1,534\\v_i=\sqrt{1534} \\=39.166 m/s[/tex]

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