starjay1520 starjay1520

15-10-2020
Mathematics

contestada

consider this polynomial equation
6(x-3)(x^2+4)(x+1)=0

the equation has ( A. 2 B.3 C.4) solutions. it's real solutions are x = (-2 -1 and 2 or. -1 and 3)

consider this polynomial equation 6x3x24x10the equation has A 2 B3 C4 solutions its real solutions are x 2 1 and 2 or 1 and 3 class=

Respuesta :

bobthebuildery20 bobthebuildery20

23-10-2020

Answer:

2 solutions

-1 and 3 is the real solutions

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