Respuesta :
Answer:
a
[tex]\mu = 127[/tex]
b
[tex]\sigma = 9.76[/tex]
c
[tex]z-score = 3.18 [/tex]
d
Yes, 158 players out of 508 is an unusual number of men born in the first 3 months of the year because the z score of 158 is greater than 3( Note :the probability of z-score = 3 is 97%)
e
The correct option is option 3
Step-by-step explanation:
From the question we are told that
The population proportion is p = 0.25
The sample size is n = 508
Generally the mean is mathematically represented as
[tex]\mu = np[/tex]
=> [tex]\mu = 508 * 0.25[/tex]
=> [tex]\mu = 127[/tex]
Generally the standard deviation is mathematically represented as
[tex]\sigma = \sqrt{ np (1-p)}[/tex]
=> [tex]\sigma = \sqrt{ 508 * 0.25 (1-0.25)}[/tex]
=> [tex]\sigma = 9.76[/tex]
Generally the z-score of 158 is mathematically represented as
[tex]z-score = \frac{158 - 127}{9.76}[/tex]
=> [tex]z-score = \frac{158 - 127}{9.76}[/tex]
=> [tex]z-score = 3.18 [/tex]
Yes, 158 players out of 508 is an unusual number of men born in the first 3 months of the year because the z score of 158 is greater than 3( Note :the probability of z-score = 3 is 97%)
What this means is that the almost the whole professional hockey league player are born in the first month which is unusual