Suppose that you borrow ​$11000 for 4 years at 6​% toward the purchase of a car. Find the monthly payments and the total interest for the loan.

Respuesta :

Answer:

The monthly payments ≅ $258.335

The total interest of the loan ≅ $1400.095

Step-by-step explanation:

The rule of the monthly payments is

[tex]M.P=\frac{P(\frac{r}{n})}{1-(1+\frac{r}{n})^{-nt}}[/tex] , where

  • P is the initial amount
  • r is the rate in decimal
  • n is the period in a year
  • t is the number of years

∵ You borrow ​$11000

P = 11000

∵ It will be for 4 years

t = 4

∵ The rate is 6%

r = 6% = [tex]\frac{6}{100}[/tex] = 0.06

∵ It is a monthly payment

n = 12

→ Substitute these values in the rule above

∴ [tex]M.P=\frac{11000(\frac{0.06}{12})}{1-(1+\frac{0.06}{12})^{-12(4)}}[/tex]

→ Use your calculator to find the answer

∴ M.P = 258.3353195

The monthly payments ≅ $258.335

→ The total interest of the loan is the difference between the total

   of the monthly payments and the initial amount

The total interest of the loan = T.M.P - P

The total of the monthly payments = M.P × t × n

∴ The total of the monthly payments = 258.3353195 × 4 × 12

The total of the monthly payments = $12400.09534

∵ The initial amount P = $11000

∴ The total interest of the loan = 12400.09534 - 11000

∴ The total interest of the loan = 1400.095

The total interest of the loan ≅ $1400.095