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The boiling point of water is 100.0*C, yet a student measured it to be 101.3*C. Calculate the percent error of the student's measurement.

Respuesta :

Neetoo

Answer:

Percent error = 1.3%

Explanation:

Given data:

Actual value of boiling point = 100.0 °C

Measured value = 101.3 °C

Percent error = ?

Solution:

Formula:

Percent error = ( Measured value - Actual value / Actual value ) × 100

Now we will put the values in formula.

Percent error =  101.3 °C - 100.0 °C / 100.0 °C × 100

Percent error =  1.3  °C / 100.0 °C × 100

Percent error =  0.013  × 100

Percent error = 1.3%

Thus, percent error is 1.3.

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