Given that: Triangle ABC is translated to triangle A'B'C' by the transformation
[tex](x,y)\to (x+2,y-5)[/tex]
The points are A(4, -4), B(2, -5), C(0, 6), D(-2, 5).
To find: Coordinates of A'.
The coordinates of A are (4,-4).
Using the given rule of transformation, we get
[tex]A(4,-4)\to A'(4+2,-4-5)[/tex]
On simplification, we get
[tex]A(4,-4)\to A'(6,-9)[/tex]
Therefore, the coordinates of point A' are (6,-9).
