Answer:
Options (E) and (G).
Step-by-step explanation:
From the data given in the table,
There is a common difference of $100 in every successive term of the amount of money.
Therefore, graph of the given table will represents a linear graph.
There are two points (5, 1200) and (6, 1300) lying on the graph.
Let the equation of the line is,
[tex]y-y_1=n(x-x_1)[/tex]
If A = Amount of money
n = Number of months
[tex]A-y_1=n(m-x_1)[/tex]
where 'n' = slope of the line
Slope = [tex]\frac{y_2-y_1}{x_2-x_1}[/tex]
= [tex]\frac{1300-1200}{6-5}[/tex]
= 100
Equation of the line passing through (6, 1300) and slope = 100
A - 1200 = 100(m - 5)
A = 100(m - 5) + 1200
A = 100m - 500 + 1200
A = 100m + 700
Therefore, Options (E) and (G) are the correct options.