Respuesta :
Answer:
(a) momentum of photon is 1.205 x 10⁻²⁷ kgm/s
velocity of electron is 1323.88 m/s
momentum of the electron is 1.205 x 10⁻²⁷ kgm/s
(b) momentum of photon is 1.506 x 10⁻²⁷ kgm/s
velocity of electron is 1654.85 m/s
momentum of the electron is 1.506 x 10⁻²⁷ kgm/s
(c) The momentum of the photon is equal to the momentum of the electron
Explanation:
(a)
wavelength of green light, λ = 550 nm
momentum of photon is given by;
[tex]p = \frac{h}{\lambda}\\\\ p = \frac{6.626 *10^{-34}}{550*10^{-9}}\\\\p = 1.205 *10^{-27} \ kg.m/s[/tex]
velocity of electron is given by;
[tex]P = \frac{h}{\lambda} \\\\mv = \frac{h}{\lambda}\\\\v = \frac{h}{m \lambda}\\\\v = \frac{6.626 *10^{-34}}{(9.1*10^{-31} )(550*10^{-9})}\\\\v = 1323.88 \ m/s[/tex]
momentum of the electron is given by;
p = mv
p = (9.1 x 10⁻³¹) (1323.88)
p = 1.205 x 10⁻²⁷ kgm/s
(b)
wavelength of red light, λ = 440 nm
momentum of photon is given by;
[tex]p = \frac{h}{\lambda}\\\\ p = \frac{6.626 *10^{-34}}{440*10^{-9}}\\\\p = 1.506 *10^{-27} \ kg.m/s[/tex]
velocity of electron is given by;
[tex]v = \frac{6.626 *10^{-34}}{(9.1*10^{-31} )(440*10^{-9})}\\\\v = 1654.85 \ m/s[/tex]
momentum of the electron is given by;
p = mv
p = (9.1 x 10⁻³¹) (1654.85)
p = 1.506 x 10⁻²⁷ kgm/s
(c) The momentum of the photon is equal to the momentum of the electron.