Respuesta :

freyabhuiyan

Answer:

a(30) = 145

Step-by-step explanation:

a(n) = a(1) + (n-1)d

d = 5

a(30) = 0 + (30-1)5

a(30) = 0 + (29)5

a(30) = 0 + 145

a(30) = 145

fichoh

Using the concept of arithmetic sequence, the value of a30, which is the 30th term of the sequence is 145

The common difference, d = 35 / 7 = 5

The nth term of an arithmetic sequence is obtained using the relation :

  • A(n) = a1 + (n - 1)d

  • a1 = first term

a1 = a2 - d = 5 - 5 = 0

Hence,

A(30) = 0 + (30 - 1)5

A(30) = 0 + 29(5)

A(30) = 145

Therefore, the value of the 30th term of the sequence is 145.

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