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given: f(x) 3x-1. g(x) 2x^2-3
=(3x-1) + (2x^2-3)
= 3x-1 + 2x^2-3
=5x^2-4

can someone tell me if its correct, im not sure if i am ;-;​

Respuesta :

MrPOOH

Solution:

f(x) = 3x - 1 = 0

f(x) = x = 1/3

By putting the value of x in g(x), we get

g(x) = 2(1/3)^2 - 3

g(x) = 2(1/9) - 3

g(x) = 2/9 - 3

g(x) = -25/9

Answer:

g(x) = -25/9

freyabhuiyan

Answer:

[tex]2x^{2} + 3x - 4[/tex]

Explanation:

(f + g)(x)=(3x-1)+(2x^2-3)

Simplify:

2x^2+3x−4

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