Respuesta :

Answer:

-1

Step-by-step explanation:

[tex](a + b)^{3} = {a}^{3} + {b}^{3} + 3ab(a + b) \\ ( - 1)^{3} = {a}^{3} + {b}^{3} + 3ab( - 1) \\ - 1 = {a}^{3} + {b}^{3} - 3ab\\ \\ \huge \red{ \boxed{{a}^{3} + {b}^{3} - 3ab = - 1}}[/tex]