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A pawn broker buys a TV set and a computer for $600. He sells the Computer at a markup of 30% and the TV at a markup of 20%. If he makes a profit of $165 on the sale of two items, what did he pay for the computer?

Respuesta :

nobillionaireNobley
Let the cost of the TV be x and that of the computer be y, then
x + y = 600 . . . . . . . (1)
0.2x + 0.3y = 165 . . (2)

From (1), x = 600 - y . . . (3)
Putting (3) into (2) gives:
0.2(600 - y) + 0.3y = 165
120 - 0.2y + 0.3y = 165
0.1y = 165 - 120 = 45
y = 45/0.1 = 450

Therefore, the computer cost him $450.

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