siremSanad8ojk
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Kelly tells you that when variables are in the denominator, the equation becomes unsolvable. "There is a value for x that makes the denominator zero, and you can't divide by zero," Kelly explains. Using complete sentences, demonstrate to Kelly how the equation is still solvable.

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meerkat18

The problem can be translated into an equation that is something like 4/5 + 3/x = 1/2 
we cannot have x equal to zero because the number can be infinite. 
So the LCD here is 10x, so multiply both sides by that to get: 
8x + 30 = 5x 
Subtract 5x and 30 from both sides: 
3x = -30 
divide: 
x = -10 
The solution isn't zero so there is a solution.

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