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the radius of the earth is 6380 km and the height of the mount everest is 8848m . if the value of the acceleration due to gravity on the top of the mount everst is 9.77m/s²,calculate the value of acceleration due to gravity on the surface of the earth .what is the weight of a body of mass 50 kg on the top of mt.everest?

Respuesta :

MathPhys

Explanation:

g = GM / R²

9.77 m/s² = GM / (6.38×10⁶ m + 8848 m)²

GM = 3.99×10¹⁴ m³/s²

At the surface of the earth:

g = GM / R²

g = (3.99×10¹⁴ m³/s²) / (6.38×10⁶ m)²

g = 9.80 m/s²

At the top of Mount Everest, the weight of a 50 kg object is:

F = mg

F = (50 kg) (9.77 m/s²)

F = 489 N

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