Answer:
71.3 g
Explanation:
molar mass of C₇H₆O₃ = 138.13 g
molar mass of [tex]C_{9}H_{8}O_{4}[/tex] = 180.17 g
find the moles of reactant: C₇H₆O₃
C₇H₆O₃ that reacted = mass/molar mass = 57.6 g C₇H₆O₃ / 138.13 g C₇H₆O₃
= 0.417 mol [tex]C_{7}H_{6}O_{3}[/tex]
From the reaction equation, 1 mole of C₇H₆O₃ yields one mole of aspirin
find theoretical yield of aspirin:
0.417 mol C7H6O3 x 180.17 g C9H8O4 / 1 mol C9H8O4[tex]\frac{0.417 mol C_{7}H_{6}O_{3}}{} x \frac{180.17 g C_{9}H_{8}O_{4}}{1 mol C_{9}H_{8}O_{4}}[/tex]
= 75.1 g C9H8O4
Actual yield= % yield × theoretical yield/100
Actual yield = 95.0 × 75.1/100
Actual yield = 71.3 g
Taking into account the reaction stoichiometry and actual yield, the mass of C₉H₈O₄ produced from 57.6 g of C₇H₆O₃ assuming 95.0% yield is 57.0285 grams.
The balanced reaction is:
22 C₇H₆O₃ (s) + 32 C₄H₆O₃ (s) → 24 C₉H₈O₄ (s) + 33 HC₂H₃O₂ (aq)
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
The mass molar of each compound is:
Then by reaction stoichiometry, the following amounts of mass of each compound participate in the reaction:
Then you can apply the following rule of three: if by stoichiometry 3036 grams of C₇H₆O₃ produce 3264 grams of C₉H₈O₄, 57.6 grams of C₇H₆O₃ will produce how many mass of C₉H₈O₄?
[tex]mass of C_{9} H_{8} O_{4} =\frac{57.6 grams of C_{7} H_{6} O_{3} x3264 gramsof C_{9} H_{8} O_{4} }{3036 grams of C_{7} H_{6} O_{3}}[/tex]
mass of C₉H₈O₄= 60.03 grams
On the other side, actual yield is the amount of product actually obtained from a reaction. Assuming 95.0% yield and considering the previously calculated mass the maximum amount of product that can be produced in the reaction, you can apply the following rule of three: If 100% equals 60.03 grams of the compound produced, 95% equals how much mass of the compound?
[tex]mass of C_{9} H_{8} O_{4} =\frac{95 percentx60.03gramsof C_{9} H_{8} O_{4} }{100 percent}[/tex]
mass of C₉H₈O₄= 57.0285 grams
Finally, the mass of C₉H₈O₄ produced from 57.6 g of C₇H₆O₃ assuming 95.0% yield is 57.0285 grams.
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