Answer:
[tex]V=162L[/tex]
Explanation:
Hello,
In this case, we can compute the required volume by using the ideal gas equation as shown below:
[tex]PV=nRT[/tex]
Thus, solving for the volume and considering absolute temperature (in Kelvins), we obtain:
[tex]V=\frac{nRT}{P}= \frac{4.70mol*0.082\frac{atm*L}{mol*K}*(21+273)K}{0.700atm} \\\\V=162L[/tex]
Best regards.