What is the length of the hypotenuse, x, if (20,21,x) is a Pythagorean triple?

Answer:
Step-by-step explanation:
[tex](20,21,x) \\Pythagoras -Theorem =\\a^2+b^2 = c^2\\\\20^2 + 21^2 = x^2\\400 + 441 = x^2\\841 = x^2\\Square -root-both-sides\\\sqrt{841} = \sqrt{x^2} \\29 = x\\\\x = 29[/tex]
Answer:
B. 29
Step-by-step explanation:
Use Pythagoras theorem.
a² + b² = c²
x is the hypotenuse.
20² + 21² = x²
400 + 441 = x²
841 = x²
√841 = √(x²)
29 = x