Respuesta :
The question is incomplete! Complete question along with answer and step by step explanation is provided below.
Question:
An object is dropped from a height of 1024 feet off the ground. The height h of the object after t seconds can be found using the equation h = 1024 − 16t^2. how much time the object will take to reach the ground?
Answer:
[tex]t = 8 \: seconds[/tex]
It will take 8 seconds for the object to reach the ground.
Step-by-step explanation:
The given equation is
[tex]h = 1024 - 16t^2[/tex]
Where h is the height in feet of the object after t seconds.
We are asked to find the time that the object will take to reach the ground.
What will be the height of the object when it hits the ground?
h = 0 ft
Yes right!
So, let us substitute h = 0 in the above equation to find the time.
[tex]h = 1024 - 16t^2 \\\\0 = 1024 - 16t^2 \\\\16t^2 = 1024 \\\\t^2 = \frac{1024}{16} \\\\t^2 = 64 \\\\t = \sqrt{64} \\\\t = \pm 8[/tex]
Since we know that time cannot be negative
[tex]t = 8 \: seconds[/tex]
Therefore, it will take 8 seconds for the object to reach the ground.
