Answer: [tex]1.07\times 10^{23}[/tex] molecules
Explanation:
According to the ideal gas equation:
PV=nRT
P = Pressure of the gas = 1 atm ( at STP)
V= Volume of the gas = 4.00 L
T= Temperature of the gas in kelvin = 273 K ( at STP)
R= Gas constant = 0.0821Latm/kmol
n= moles of gas= ?
Putting in the values we get:
[tex]1atm\times 4.00L=n\times 0.0821Latm/Kmol\times 273K[/tex]
[tex]n=0.178mol[/tex]
Now 1 mole of any substance contains [tex]6.023\times 10^{23}[/tex] molecules at STP
Thus 0.178 mole of any substance contains = [tex]\frac{6.023\times 10^{23}}{1}\times 0.178=1.07\times 10^{23}[/tex] molecules at STP
Thus there are [tex]1.07\times 10^{23}[/tex] gaseous molecules in the flask.