Answer:
12 m
Step-by-step explanation:
Given data
θ= 10°
Horizontal length is equivalent to the adjacent= 20 m
the height of the ramp is equivalent to the opposite=?
Applying SOH CAH TOA we have
using TOA
Tan θ= opp/adj
Tan 10= opp/20
opp= Tan(10)* 20
opp= 0.64836*20
opp= 12.96
Approximately the maximum height of the ramp is 12 m
