Respuesta :

Step-by-step explanation:

2,

[tex](a.y^{3} +3y^{2} -3 ) = (ay^{2} +(4a+3)y +4(4a+3))(y-4) +64a+45[/tex]

so A = 64a +45

([tex]2y^{3} -5y+a =(2y^{2} +8y +27)(y-4) +108 +a[/tex]

so B = 108 +a

2A-B=0--> 2(64a+45)-108-a=0--> a =18/127

3,

(3x+2y)^3 = 27x^3 +54x^2.y + 36x.y^2 +8y^3 = 27x^3 +8y^3 +2 +18xy(3x +2y) = 20^3

so P = 27x^3 +8y^3 = 20^3 - 18.xy(3x+2y)= 7440