Line A has equation 3x-4y=5
Line B goes through the points (4, 7) and (–1, 3)

Are lines A and B parallel?

(4 marks)

Gradient of Line A (as a decimal):
Gradient of Line B (as a decimal):
Therefore the lines parallel

Respuesta :

Step-by-step explanation:

line A can be written as y1= 3/4.x -5/4

line B is a linear function : y2= ax +b

4a+b=7 and -a +b =3 so a=4/5 and b=19/5

so y2=4/5x +19/5

so they are not parallel

Line A goes through (0,-5/4) and (1,-1/2)

Gradient of line A = G1= (-1/2 - (-5/4))/(1-0) =3/4=0.75

Gradient of line B= G2= (7/3)/(4-(-1))=4/5=0.8

The Line A and Line B are not parallel to each other.

Equation of line :

The equation of line A is,

                           [tex]3x-4y=5[/tex]

Now write in slope intercept form,

                       [tex]3x-4y=5\\\\4y=3x-5\\\\y=\frac{3}{4} x-\frac{5}{4}[/tex]

Slope of line A is [tex]\frac{3}{4}[/tex].

Equation of line B is,

                    [tex]y-7=\frac{3-7}{-1-4}(x-4) \\\\y-7=\frac{4}{5} x-\frac{16}{5}\\ \\y=\frac{4}{5} x+\frac{19}{5}[/tex]

Slope of line B is [tex]\frac{4}{5}[/tex]

Since, the slope of both line A and B are different. therefore, Line A and Line B are not parallel to each other.

Learn more about the parallel lines here:

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