I need help plz someone help me solved this problem I need help ASAP! I will mark you as brainiest!

Step-by-step explanation:
y = [tex]{\log_b x}[/tex]
if x =4 then y = [tex]{\log_b 4}[/tex] =-1 --> [tex]b^{-1}[/tex] =4 --> b= 1/4
Answer:
b = 1/4
Step-by-step explanation:
It has to be a log because for x=0, b⁰ should be 1 for every b and that is not the case here.
Remember that [tex]y = \log_bx[/tex] means that [tex]b^y=x[/tex].
Since the point (4,-1) seems to be on the line, we can solve:
b⁻¹ = 4
so b = 1/4