Answer:
the two vehicles will be moving at a speed of 6.16 m/s
Explanation:
This is a case of completely inelastic collision, therefore, the conservation of momentum can be written as:
[tex]m_1\,v_1+m_2\,v_2=(m_1+m_2)\,v_f[/tex]
which given the information provided results into:
[tex]m_1\,v_1+m_2\,v_2=(m_1+m_2)\,v_f\\(1250)\,(0)+(3550)\,(8.33)=(1250+3550)\,v_f\\29571.5=4800\,v_f\\v_f=6.16\,\,m/s[/tex]