Answer:
E = 1.50 × [tex]10^{8}[/tex] V/m
Explanation:
given data
B = 0.50 T
solution
we know that energy density by the magnetic field is express as
[tex]\mu _b = \frac{B}{2\mu _o}[/tex] ...............1
and
energy density due to electric filed is
[tex]\mu _e = \frac{\epsilon _o E^2}{2}[/tex] ...............2
and here [tex]\mu _b = \mu _ e[/tex]
so that
E = [tex]\frac{B}{\sqrt{\mu _o \times \epsilon _o}}[/tex] ...................3
put here value and we get
[tex]E = \frac{0.50}{\sqrt{4\pi \times 10^{-7} \times 8.852 \times 10^{-12}}}[/tex]
E = 3 × [tex]10^{8}[/tex] × 0.50
E = 1.50 × [tex]10^{8}[/tex] V/m
