A gas sample is collected in a 0.279 L container at 22.7 °C and 0.764 atm. If the sample has a mass of 0.320 g, what is the identity of the gas? Group of answer choices g

Respuesta :

Answer:

HCl

Explanation:

Choices:

CO: 28.01g/mol

NO₂: 46g/mol

CH₄: 16.04g/mol

HCl: 36.4g/mol

CO₂: 44.01g/mol

It is possible to identify a substance finding its molar mass (That is, the ratio between its mass in grams and its moles). It is possible to find the moles of the gas using general ideal gas law:

PV = nRT

Where P is pressure of gas 0.764atm; V its volume, 0.279L; n moles; R gas constant: 0.082atmL/molK and T its absolute temperature, 295.85K (22.7°C + 273.15).

Replacing:

PV = nRT

PV / RT = n

0.764atm*0.279L / 0.082atmL/molKₓ295.85K = n

8.786x10⁻³ = moles of the gas

As the mass of the gas is 0.320g; its molar mass is:

0.320g / 8.786x10⁻³moles = 36.4 g/mol

Based in the group of answer choices, the identity of the gas is:

HCl

Molar mass of substance is the mass of one mole of substance. The gas is identified as HCl as it has 36.4 g/mol of molar mass.

The substance can be identified from its molar mass. The formula to calculate the molar mass is

[tex]\bold {m = \dfrac w{n}}[/tex]

Where,

n - number of moles

w - given mass of the substance  

The number of moles can be calculated by the using  ideal gas law

PV = nRT

[tex]\bold {n = \dfrac {PV }{ RT }}[/tex]  

Where

P - pressure of gas 0.764 atm;

V its volume, 0.279 L;

n moles;

R gas constant: 0.082atmL/molK

T its absolute temperature, 295.85 K (22.7°C + 273.15).  

Put the values in the formula,  

[tex]\bold {n = \dfrac {0.764\ atm \times , 0.279 }{ 0.082 \times 295.85 }}\\\\\bold {n =8.786x10^-^3}[/tex]  

 

Now, put the values in the molar mass formula,

[tex]\bold {m = \dfrac {0.320g}{ 8.786x10^-^3} = 36.4\ g/mol}[/tex]

Therefore, the gas is identified as HCl as it has 36.4 g/mol of molar mass.

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