Answer:
[tex] b. \: a_n =4+ 3(n-1)[/tex]
Step-by-step explanation:
Given Arithmetic sequence is: 4, 7, 10, 13
Here,
First term (a) = 4
Common Difference (d) = 7 - 4 = 3
nth term of an Arithmetic sequence is given as:
[tex] a_n = a + (n-1)d[/tex]
Substituting the values of a and d in the above sequence, we find:
[tex] a_n = 4 + (n-1)\times 3\\
\therefore a_n =4+ 3(n-1)\\
\huge \red {\boxed {\therefore a_n =4+ 3(n-1)}} \\
[/tex]
