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PLEASE HELP! I WILL MARK BRAINLIEST! tight guitar string has a frequency of 560 Hz as its third harmonic. What will be its fundamental frequency if it is fingered at a length of only 60% of its original length?

Respuesta :

Answer:

Original fundamental frequency = 311.111 Hz (Approx)

Explanation:

Given:

Frequency (f) = 560 Hz

3rd harmonic

Used length = 60%

Find:

Original fundamental frequency.

Computation:

Fundamental frequency = Frequency (f) / 3rd harmonic

Fundamental frequency = 560 / 3

Original fundamental frequency = 560 / 3(60%)

Original fundamental frequency = 560 / 1.8

Original fundamental frequency = 311.111 Hz (Approx)

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