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Compute the end-to-end separation (direct distance between molecule ends), in Angstroms, of a coiled PVC molecule with a number-average molecular weight of 256,131 g/mol, given that the tetrahedral bond angle is 109.5o and the carbon-carbon bond length is 1.54 Angstroms. Answer Format: X (no decimal)

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Answer:

5156  Â

Explanation:

Chains of monomers that are being linked together constitute what is called polymers. in this question; we are to compute the end to end separation (direct distance between molecule ends), in Angstroms, of a coiled PVC molecule.

Using the following approach:

The first step is to determine the repeating units in polymer

The number of repeating unit = average molecular weight/  atomic weight of PVC

Given that:

average molecular weight = 256,131 g/mol

atomic weight of PVC = 62.498 g

Then;

The number of repeating unit = 256,131 g/mol /  62.498 g = 4098.227143 mol

Now the distance is calculated by using the formula:

d = (C-C) × sin 109.5/2

C-C bond length = 1.54 angstroms

tetrahedral bond angle = 109.5°

Then d = (1.54)  × sin 109.5/2

d = 1.258

Thus ; the end to end separation  is :

4098.227143  × 1.258 = 5155.57 Â

The answer is 5156  Â (since no decimal should be included )

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