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Express the worst case run time of these pseudo-code functions as summations. You do not need to simplify the summations. a) function(A[1...n] a linked-list of n integers) for int i from 1 to n find and remove the minimum integer in A endfor endfunction

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Answer:

The answer is "O(n2)"

Explanation:

The worst case is the method that requires so many steps if possible with compiled code sized n. It means the case is also the feature, that achieves an average amount of steps in n component entry information.

  • In the given code, The total of n integers lists is O(n), which is used in finding complexity.
  • Therefore, O(n)+O(n-1)+ .... +O(1)=O(n2) will also be a general complexity throughout the search and deletion of n minimum elements from the list.

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