Answer:
9.375 V/m
Explanation:
number of turns, N = 50
diameter of the coil, 2r = 15 cm
r = 7.5 cm = 0.075 m
magnetic field, B = 0.5 T
final magnetic field, B' = 0 T
time required, t = 0.1 s
flux, Ф = N B A Cos 0°
[tex]\frac{d\phi}{dt}=NA\frac{dB}{dt}[/tex]
[tex]\frac{d\phi}{dt}=50\times \pi r^{2}\times \frac{0-0.5}{0.1}[/tex]
[tex]\frac{d\phi}{dt}=-250\times \pi r^{2}[/tex]
According to the Maxwell's equation
[tex]\oint \overrightarrow{E}.d\overrightarrow{l}=-\frac{d\phi}{dt}[/tex]
[tex]E\times 2\pi r = 250 \times \pi\times r^{2}[/tex]
E = 125 x r
E = 125 x 0.075
E = 9.375 V/m
Thus, the electric field is 9.375 V/m.
