Answer:
[tex]F = 7525440\,lbf[/tex]
Explanation:
The force that the structural base must withstand the weight of water:
[tex]F = \rho_{w}\cdot V\cdot g[/tex]
[tex]F = (62.4\,\frac{lbm}{ft^{3}} )\cdot (0.9\times 10^{6}\,gal)\cdot \left(\frac{0.134\,ft^{3}}{1\,gal} \right)\cdot (32.1\,\frac{ft}{s^{2}} )\cdot \left(\frac{1\,lbf}{32.1\,lbm} \right)[/tex]
[tex]F = 7525440\,lbf[/tex]
