Respuesta :

dalendrk
[tex]A(x_A;\ y_A);\ B(x_B;\ y_B)\\\\midpoint\ of\ AB\ \left(\dfrac{x_A+x_B}{2};\ \dfrac{y_A+y_B}{2}\right)\\---------------------\\\\A(9;\ 8);\ B(-1;-2)\\\\midpoint\ of\ AB:\left(\dfrac{9+(-1)}{2};\ \dfrac{8+(-2)}{2}\right)=\left(\dfrac{8}{2};\ \dfrac{6}{2}\right)\\\\\boxed{\boxed{(4;\ 3)}}[/tex]
AL2006
The midpoint of is (4,3).