Respuesta :
Answer:
192 feet.
Step-by-step explanation:
h)t) = -16t^2 + 88t + 80 therefore:
h(2) = - 16(2)^2 + 88*2 + 80
= -64 + 176 + 80
= 112 + 80
= 192 feet.
the height of the rocket after 2 seconds of launched from the top of an 80-foot cliff with an initial velocity of 88 feet per second is 192 ft.
What is the equation of motion?
The equation of motion is the relation between the distance, velocity, acceleration and time of a moving body.
A rocket is launched from the top of an 80-foot cliff with an initial velocity of 88 feet per second.
The height of the rocket t seconds after launch is given by the equation [tex]h=-16t^2+88t + 80[/tex]
Here, (h) is the height and (t) is the time.
The value of height after the 2 second of launched has to be find out. Put the value of time as 2 in the above equation to find the value of height.
[tex]h=-16(2)^2+88(2) + 80\\h=-64+176+80\\h=192\rm\; ft[/tex]
Hence, the height of the rocket after 2 seconds of launched from the top of an 80-foot cliff with an initial velocity of 88 feet per second is 192 ft.
Learn more about the equation of motion here;
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