Answer:
[tex]x\in <-9, 9>[/tex]
Step-by-step explanation:
[tex]-\frac{8}{3}<\frac{x+1}{3}<\frac{10}{3}; x\in R[/tex]
Separate the inequalities.
[tex]\frac{x+1}{3}>-\frac{8}{3};\frac{x+1}{3}<\frac{10}{3}[/tex]
Multiply by the denominator (3) on both sides.
[tex]3\times\frac{x+1}{3}>-\frac{8}{3}\times 3= x+1>-8[/tex]
Subtract 1 from both sides.
[tex]x+1(-1)>-8(-1)\\\\x>-9[/tex]
Repeat aforementioned steps for the second inequality.
[tex]3\times\frac{x+1}{3}<\frac{10}{3}\times3=x+1(-1)>10(-1)\\\\x<9[/tex]
