7 + 6 = 9 + 4
16 - 7 = 3 + 6
20 x 6 = 60 x 2
2 x (3 + 5) = 20 - 4
3 + (3 x 6) = 3 + 3 + 15
Solution:
Given that, we have to find the missing numbers in each equation
First equation:
Let the unknown be "x"
7 + x = 9 + 4
Solve the right side of equation, 9 + 4 = 13
7 + x = 13
x = 13 - 7
x = 6
Second equation:
Let the unknown be "x"
16 - 7 = 3 + x
Solve the left side of equation, 16 - 7 = 9
9 = 3 + x
x = 9 - 3
x = 6
Third Equation:
[tex]D \times 6 = 60 \times 2\\\\D \times 6 = 120\\\\D = \frac{120}{6}\\\\D = 20[/tex]
Fourth Equation:
[tex]2 \times (3 + 5) = x - 4\\\\Solve\ for\ brackets\\\\2 \times 8 = x - 4\\\\16 = x - 4\\\\x = 16 + 4\\\\x = 20[/tex]
Fifth Equation:
Let the unknown be "x"
[tex]x + ( 3 \times 6) = x + x + 15\\\\Solve\ for\ brackets\\\\x + 18 = 2x + 15\\\\Combine\ the\ like\ terms\\\\2x - x = 18 - 15\\\\x = 3[/tex]
